What is the mass of $4.75 \cdot 10^{21}$ $4.75 * 10^21$ platinum atoms?

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Answer 1 · 2016-02-13T17:27:52

$1.54 g$ $1.54g$

$6.023 \times 10^{23}$ $6.023xx10^23$ Pt atoms constitutes $1$ $1$ mole of Pt.

Hence, by ratio and proportion, $4.75 \times 10^{21}$ $4.75xx10^21$ atoms constitutes $0.0078864$ $0.0078864$ moles.

Hence the mass will be the product of the moles with the molar mass,

$m = n \times M_{r}$ $m=nxxM_r$

$= 0.0078864 m o l \times 195.1 g / m o l$ $=0.0078864molxx195.1g//mol$

$= 1.54 g$ $=1.54g$ .

What is the mass of 4.75⋅10214.75 * 10^21 platinum atoms?