Question

What is the mass of `5.42` `cm^3` of table sugar?

Answer 1

From this site I learnt that the density of table sugar is `700` `kg*m^-3`. So the answer is a bit under `4` `g`.

Explanation:

In handier units this is: `700*cancel(kg)*cancel(m^-3)xx10^3*g*cancel(kg^-1)xx10^-6*cancel(m^(3))*cm^-3` `=` `0.7*g*cm^-3`, or `0.7*g*mL`.

So (finally) the answer to your question is `5.42*cancel(cm^-3)xx0.7*g*cancel(cm^3)` `=` `4*g` approximately!

It is a fact that sugar DOES NOT dissolve in hexanes. Given that `rho_"hexanes"` `=` `0.67*g*mL`, should sugar float in hexanes? Can you account for the fact that sucrose, `C_12H_22O_11` is insoluble in hexanes?