What is the mass of #9.34 * 10^24# molecules of water?

1 Answer
José F.
Feb 7, 2016

279.4 grams

Explanation:

1 mol of water (18.015 g) is #6.022xx10^23# molecules of water.

If we divide #9.34xx10^24# by #6.022xx10^23# gives 15.51 mols

Therefore that amount of water molecules is:

#15.51 mol xx 18.015g/(mol) =279.4 grams#

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