# What is the mass of 9.34 * 10^24 molecules of water?

Feb 7, 2016

279.4 grams

#### Explanation:

1 mol of water (18.015 g) is $6.022 \times {10}^{23}$ molecules of water.

If we divide $9.34 \times {10}^{24}$ by $6.022 \times {10}^{23}$ gives 15.51 mols

Therefore that amount of water molecules is:

$15.51 m o l \times 18.015 \frac{g}{m o l} = 279.4 g r a m s$