What is the maximum number of 3-digit conscequetive integers that have atleast one odd digit?
997, 998 and 999.
If the numbers have at least one odd digit, in order to get the highest numbers let's chose 9 as the first digit. There is no restriction on the other digits, so the integers can be 997, 998 and 999.
Or you wanted to say at THE MOST one odd digit.
So let's chose 9 again. The other digits can not be odd. Since in three consecutive numbers, at least one must be odd, we cannot have three consecutive numbers in which 9 is the first digit.
So, we have to reduce the first digit to 8. If the second digit is 9, we can't have three consecutive numbers only with even numbers,unless the last of these numbers i 890, and the others are 889 and 888.
If I am interpreting the question correctly, it is asking for the length of the longest sequence of consecutive
Any such sequence would necessarily include either
We can discard
Counting down, as all of the
each of which has a length of