What is the molar mass of ammonium carbonate?

Dec 27, 2016

$96.09 \frac{g}{m o l}$

Explanation:

Let's start off with the chemical formula of ammonia carbonate, which is ${\left(N {H}_{4}\right)}_{2} C {O}_{3}$

Now, we can determine the molar mass of this ionic compound by using the following equation:

atomic weight of element $\times$number of atoms given by subscript $=$ formula mass

First, you want to have a periodic table available so you can determine the atomic weight of N, H, C, and O:

• N has a molar mass of 14.01 g/mol
• H has an atomic weight of 1.008 g/mol
• C has an atomic weight of 12.01 g/mol
• O has an atomic weight of 16.00 g/mol

From the chemical formula, we have 2 nitrogen atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 28.02 g/mol.

There are 8 hydrogen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 8.064 g/mol

Next, you have 1 carbon atoms, so the atomic mass of C is 12.01 g/mol

And, there are 3 oxygen atoms, so the atomic mass has to be multiplied by 3, which gives you a value of 48.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

$\textcolor{b l u e}{\text{28.02 g/mol + 8.064 g/mol + 12.01 g/mol + 48.00 g/mol = 96.09 g/mol}}$