# What is the molar mass of aspirin, C_9H_8O_4?

Approx. $180 \cdot g \cdot m o {l}^{-} 1$
So, $\text{Molar mass of } {C}_{9} {H}_{8} {O}_{4}$ $=$ $\left(9 \times 12.011 + 8 \times 1.00794 + 4 \times 15.999\right) \cdot g \cdot m o {l}^{-} 1$ $=$ ??*g*mol^-1.