# What is the molar mass of Fe_3(PO_4)_2?

Dec 18, 2015

$357.475 \text{g/mol}$

#### Explanation:

Take the sum of the molar masses of each individual element.

There are:

$3$ $\text{Fe}$ atoms
$2$ $\text{P}$ atoms
$8$ $\text{O}$ atoms

Notice that the term outside the parentheses can be multiplied into the parentheses to show how many atoms there are of each element in the compound.

$3 \times \text{molar mass of Fe"=3xx55.845"g/mol"=167.535"g/mol}$

$2 \times \text{molar mass of P"=2xx30.974"g/mol"=61.948"g/mol}$

$8 \times \text{molar mass of O"=8xx15.999"g/mol"=127.992"g/mol}$

The sum of the individual molar masses is

$\textcolor{red}{357.475} \text{ g/mol}$