What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF?

1 Answer
Mar 12, 2017

Answer:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

Explanation:

And thus, here, #"Molarity"# #=# #((52*cancelg)/(25.9*cancelg*mol^-1))/(1.5*L)=1.3*mol*L^-1#, with respect to lithium fluoride

Now it is a fact that this solution would have a #pH>7#. Given that #HF(aq)# is a fairly weak acid, why should this be so?