Question

What is the molarity of a sample of sulfuric acid if 28.00 mL of 0.18 M NaOH was required to titrate 10 mL of the sulfuric acid?

Answer 1

Approx. `0.25*mol*L^-1............` with respect to `H_2SO_4`

Explanation:

We need (i) a stoichiometric equation:

`H_2SO_4(aq) + 2NaOH(aq) rarr Na_2SO_4(aq) + 2H_2O(l)`

And (ii) equivalent quantities of sodium hydroxide.........

`"Moles of NaOH"=28.00xx10^-3Lxx0.18*mol*L^-1=5.040xx10^-3*mol`

And thus `[H_2SO_4]=(1/2xx5.040xx10^-3*mol)/(10xx10^-3L)=??`