# What is the molarity of a solution in which there are 25 gms of Na_2SO_4 in 500 mL solution?

Feb 2, 2017

$\text{Molarity} \cong 0.4 \cdot m o l \cdot {L}^{-} 1$ with respect to sodium sulfate.
$\text{Concentration, molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$.
((25*cancelg)/(142.0*cancelg*mol^-1))/(500*cancel(mL)xx10^-3*L*cancel(mL^-1))=??*mol*L^-1