# What is the molecular, total ionic, and net ionic equations of these reactions? "AuBr"_3+"H"_2"CO"_3" and "Bi(NO"_3)_3+"BaS"

## I am not sure on how I need to solve these types of problems

Jul 29, 2018

Refer to the explanation.

#### Explanation:

If you are being asked for the molecular, total ionic, and net ionic equations, the reactions are double replacements (displacements). The reactants are two solutions. In double replacements, the positive ions and negative ions in the two solutions switch places to form the products.

$\textcolor{red}{\text{A"color(blue)"X" + color(magenta)"B"color(purple)"Y}}$$\rightarrow$$\textcolor{red}{\text{A"color(purple)"Y" + color(magenta)"B"color(blue)"X}}$,

where:

$\textcolor{red}{\text{A}}$ and $\textcolor{m a \ge n t a}{\text{B}}$ are positive ions and $\textcolor{b l u e}{\text{X}}$ and $\textcolor{p u r p \le}{\text{Y}}$ are negative ions.

If a double replacement reaction occurs, one product must be an insoluble solid (precipitate), an insoluble gas, or water (a neutralization reaction). If one product is not water or a gas, then it may be a precipitate. We can determine this by consulting a chart of solubility rules like the one below. First Reaction: "AuBr"_3("aq") + "H"_2"CO"_3("aq")

Molecular Equation

Balanced Chemical Equation

"2AuBr"_3("aq") + "3H"_2"CO"_3("aq")$\rightarrow$$\text{Au"_2"(CO"_3)_3darr +"6HBr(aq)}$

The down arrow means that the compound is precipitate, which is an insoluble solid that precipitated out of solution.

Complete Ionic Equation

Includes all of the ions, including the ones that are not part of the reaction, which are called spectator ions.

"2Au"^(3+)("aq") + "6Br"^(-)("aq") + "6H"^(+) + "CO"_3^(2-)("aq")$\rightarrow$"Au"_2"(CO"_3)_3darr+ "6H"^(+)("aq") + "6Br"^(-)("aq")

Net Ionic Equation

Includes only the ions that reacted. Does not contain the spectator ions.

$\text{2Au"^(3+)("aq")+"CO"_3^(2-)("aq")}$$\rightarrow$$\text{Au"_2"(CO"_3)_3darr}$

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Second Reaction: $\text{Bi(NO"_3)_3("aq")+"BaS(aq)}$

Molecular Equation

$\text{2Bi(NO"_3)_3+"3BaS}$$\rightarrow$$\text{Bi"_2"S"_3darr + "3Ba(NO"_3)_2("aq")}$

Complete Ionic Equation

"2Bi(aq) + 6NO"_3^(-)("aq") + "3Ba"^(2+)("aq") + "3S"^(2-)("aq")$\rightarrow$$\text{Bi"_2"S"_3darr + "3Ba"^(2+)"aq" + "6NO"_3^(-)("aq")}$

Net Ionic Equation

"2Bi(aq)+3S"^(2-)("aq")$\rightarrow$${\text{Bi"_2"S}}_{3} \downarrow$