# What is the moment of inertia of a 5.00 kg 34.0 cm radius hoop about its normal axis?

I found: $I = M {R}^{2} = 0.578 k g {m}^{2}$
so $I = 5 \times {\left(\frac{34}{100}\right)}^{2} = 0.578 k g {m}^{2}$