What is the moment of inertia of a pendulum with a mass of #2 kg# that is #12 m# from the pivot?

1 Answer
Apr 15, 2017

Answer:

MOMENT OF INERTIA = # MR^2 #

Explanation:

moment of inertia is defined as : # intdmr^2 #
where dm is the mass of the differential element of the body and r is the distance of that differential element from the point about which you want to find out the moment of inertia .
thus , moment of inertia of a pendulum is = # mr^2 #
m - mass of the bob
r - distance of bob from the pivot
with the assumption that the string connecting bob and the pivot is massless and inextensible .
therefore , moment of inertia = # 2 * 12^2 #
# = 288 kgm^2 #