# What is the moment of inertia of a pendulum with a mass of 2 kg that is 12 m from the pivot?

Apr 15, 2017

MOMENT OF INERTIA = $M {R}^{2}$

#### Explanation:

moment of inertia is defined as : $\int \mathrm{dm} {r}^{2}$
where dm is the mass of the differential element of the body and r is the distance of that differential element from the point about which you want to find out the moment of inertia .
thus , moment of inertia of a pendulum is = $m {r}^{2}$
m - mass of the bob
r - distance of bob from the pivot
with the assumption that the string connecting bob and the pivot is massless and inextensible .
therefore , moment of inertia = $2 \cdot {12}^{2}$
$= 288 k g {m}^{2}$