# What is the moment of inertia of a pendulum with a mass of 7 kg that is 10 m from the pivot?

Feb 6, 2016

$700 k g . {m}^{2}$

#### Explanation:

Assuming it is a simple pendulum, (dimensions small and mass of string negligible), we may find the moment of inertia of the pendulum bob about the axis of rotation as follows :

$I = M {R}^{2}$

$= 7 \times {10}^{2}$

$= 700 k g . {m}^{2}$