# What is the moment of inertia of a pendulum with a mass of 8 kg that is 5 m from the pivot?

Mar 7, 2018

I get the moment of inertia as $I = 200 \setminus {\text{kg m}}^{2}$.

#### Explanation:

Moment of inertia of a simple pendulum is given by

$I = m {r}^{2}$

So here, $m = 8 \setminus \text{kg}$, $r = 5 \setminus \text{m}$

So, we have

$I = 8 \setminus {\text{kg"*25 \ "m}}^{2}$

$= 200 \setminus {\text{kg m}}^{2}$

Source:

https://en.wikipedia.org/wiki/Moment_of_inertia#Simple_pendulum