What is the moment of inertia of a rod with a mass of 3 kg and length of 7 m that is spinning around its center?

Feb 5, 2016

$12.25 k g . {m}^{2}$

Explanation:

The formula for moment of inertia of a thin rod of mass M and length L about an axis through its centre is given by

$I = \frac{1}{12} M {L}^{2}$

$= \frac{1}{12} \times 3 \times {7}^{2}$

$= 12.25 k g . {m}^{2}$