Question

What is the moment of inertia of a rod with a mass of `3 kg` and length of `7 m` that is spinning around its center?

Answer 1

`12.25kg.m^2`

Explanation:

The formula for moment of inertia of a thin rod of mass M and length L about an axis through its centre is given by

`I=1/12ML^2`

`=1/12xx3xx7^2`

`=12.25kg.m^2`