Question

What is the moment of inertia of a rod with a mass of `6 kg` and length of `1 m` that is spinning around its center?

Answer 1

`0.5kg.m^2`

Explanation:

In this case, `I=1/12ML^2`

`=1/12xx6xx1^2`

`=0.5kg.m^2`.

(Let me know if you want me to show you the derivation of the equation for `I=1/12ML^2` from definition/first principles then I will)