# What is the moment of inertia of a rod with a mass of 6 kg and length of 15 m that is spinning around its center?

Jan 24, 2016

$112.5 k g . {m}^{2}$

#### Explanation:

The formula for momentum of inertia of a thin rod of mass $M$ and length $L$ about an axis through its centre is given by

$I = \frac{1}{12} M {L}^{2}$

$= \frac{1}{12} \times 6 \times {15}^{2}$

$= 112.5 k g . {m}^{2}$