Question

What is the moment of inertia of a rod with a mass of `6 kg` and length of `15 m` that is spinning around its center?

Answer 1

`112.5kg.m^2`

Explanation:

The formula for momentum of inertia of a thin rod of mass `M` and length `L` about an axis through its centre is given by

`I=1/12ML^2`

`=1/12xx6xx15^2`

`=112.5kg.m^2`