What is the multiplicative inverse of #- \frac{z^3}{2xy^2}#?

1 Answer
Jan 21, 2015

The muplticative inverse of a number #x# is, by definition, a number #y# such that #x\cdot y=1#.

So, in case of integer numbers #n#, the multiplicative inverse of #n# is simply #\frac{1}{n}#, and thus it's not an integer number.

In the case of fractions, instead, the multiplicative inverse of a fraction is still a fraction, and it's simply a fraction with the same positivity of the original one, and with numerator and denominator flipped over: the multiplicative inverse of #\frac{a}{b}# is the fraction #\frac{b}{a}#. So, in your case, the multiplicative inverse of #-\frac{z^3}{2xy^2}# is #-\frac{2xy^2}{z^3}#.