What is the net ionic equation for the reaction #Na^+(aq) + C_2H_3O_2^-(aq) + H^+ (aq) + Cl^- (aq) -> Na^+(aq) + Cl^- (aq) + HC_2H_3O_2(aq)#?

1 Answer
Mar 29, 2017

#C_2H_3O_2^-)(aq) + H^+(aq) = HC_2H_3O_2(l)#

Explanation:

For determining net-ionic reaction from an ionic reaction you must cut out the ions which are same. One of the product is (gaseous), (liquid) but it is not (aq)
For instance #HC_2H_3O_2# is the (l) here

#Na^+(aq) + C_2H_3O_2^-)(aq) + H^+(aq) + Cl^-) = Na^+(aq) + Cl^-)(aq) + HC_2H_3O_2(l)#

Cut out the same ions

#cancel(Na^+(aq)) + C_2H_3O_2^-)(aq) + H^+(aq) +cancel( Cl^-) = cancel(Na^+(aq)) + cancel(Cl^-)(aq) = HC_2H_3O_2(l)#

#C_2H_3O_2^-)(aq) + H^+(aq) = HC_2H_3O_2(l)#