# What is the norm of < -3, -4 , -2 >?

$\vec{c} = \sqrt{29}$
"the norm of a vector is given as : "vec c=sqrt (Delta x^2+Delta y^2+Delta z^2
$\vec{c} = \sqrt{{\left(- 3\right)}^{2} + {\left(- 4\right)}^{2} + {\left(- 2\right)}^{2}}$
$\vec{c} = \sqrt{9 + 16 + 4}$
$\vec{c} = \sqrt{29}$