Question

What is the norm of `< -5 , 4 , 5 >`?

Answer 1

`sqrt 66`

Explanation:

The standard (Euclidean) norm of a vector `vec a = (a_1,a_2,a_3)` is

`||vec a|| =sqrt(a_1^2+a_2^2+a_3^2)`

So, for the given vector, the norm is

`sqrt((-5)^2+4^2+5^2) = sqrt 66`