What is the norm or $<1,6,-1 >$ ?

Question

1351 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-26T12:42:34

The norm is $=6.16$

Let $vecv= <1,6,-1>$

The norm of $vecv$ is

$=||<1,6,-1>||$

$=sqrt(1+36+1)$

$=sqrt38$

$=6.16$

What is the norm or <1,6,-1 ><1,6,-1 >?