What is the norm or $< 1, 6, - 1 >$ $<1,6,-1 >$ ?

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Answer 1 · 2017-03-26T12:42:34

The norm is $= 6.16$ $=6.16$

Let $\to v = < 1, 6, - 1 >$ $vecv= <1,6,-1>$

The norm of $\to v$ $vecv$ is

$= | | < 1, 6, - 1 > | |$ $=||<1,6,-1>||$

$= \sqrt{1 + 36 + 1}$ $=sqrt(1+36+1)$

$= \sqrt{38}$ $=sqrt38$

$= 6.16$ $=6.16$

What is the norm or <1,6,−1><1,6,-1 >?