# What is the norm or <5,2,-7 >?

Jan 21, 2017

The answer is $= \sqrt{78}$

#### Explanation:

The norm of a vector $< a , b , c >$ is

$| | < a , b , c > | | = \sqrt{{a}^{2} + {b}^{2} + {c}^{2}}$

Therefore,

$| | < 5 , 2 , - 7 > | | = \sqrt{25 + 4 + 49} = \sqrt{78}$