What is the number of H atoms in 0.183 mole #C_6H_14O#?

1 Answer
Nov 16, 2015

Answer:

There are #1.54xx10^24"H atoms"# in #"0.183 mol C"_6"H"_14"O"#.

Explanation:

One mole of #"C"_6"H"_14"O"# contains 14 moles of hydrogen atoms. This can be written as #(14"mol H atoms")/(1"mol C"_6"H"_14"O")#.

To determine how many moles of hydrogen are contained in #"0.183 mol C"_6"H"_14"O"#, multiply #"0.183 mol C"_6"H"_13"O"# times 14 moles of H atoms per 1 mole of #"C"_6"H"_14"O"#. Then multiply times #6.022xx10^23 "atoms H"#.

#0.183cancel("mol C"_6"H"_14"O")xx(14cancel("mol H" "atoms"))/(1cancel("mol C"_6"H"_14"O"))xx(6.022xx10^23"H atoms")/(1cancel("mol H atoms"))=1.54xx10^24 "H atoms"#