Question

What is the oblique asymptote of `f(x)=(x^2+x-2)/(x+1)`?

Answer 1

The oblique asymptote is `y = x`

Explanation:

`f(x) = (x^2+x-2)/(x+1) = (x(x+1)-2)/(x+1) = x - 2/(x+1)`

As `x->+-oo`, `-2/(x+1) -> 0`.

So `f(x)` is asymptotic to the line `y = x`.