# What is the ordered pair of the origin of the square root function g(x)=\sqrt{x+4}+6?

##### 1 Answer
Nov 14, 2014

The origin of $y = \sqrt{x}$ is $\left(0 , 0\right)$.

By shifting left by 4 units, the origin of $y = \sqrt{x + 4}$ moves to $\left(- 4 , 0\right)$.

By shifting up by 6 units, the origin of $g \left(x\right) = \sqrt{x + 4} + 6$ moves to $\left(- 4 , 6\right)$. The graph of $y = g \left(x\right)$ looks like:

I hope that this was helpful.