Question

What is the ordered pair solution when x=2 `f(x)=2x^3+x^2-10x-5`?

Answer 1

`(2, -5)`

Explanation:

Simply plug in `x=2` into `f(x)=2x^3+x^2-10x-5` to determine the `y-`coordinate.

`f(2)=2(2)^3+2^2-10(2)-5=2(8)+4-20-5`

`f(2)=16+4-20-5=-5`

The ordered pair is then `(2, -5)`