# What is the oxidation number of carbon in Na2C2O4?

##### 2 Answers

#### Explanation:

You need to do a little algebra on this one.

You have the substance

Converting this into numbers based on their known oxidation states, you will have:

Na = 2 (+1) = +2

C = 2 (x) = 2x, where x is the unknown

O = 4 (-2) = -8

Hence,

(+2) + 2x + (-8) = 0

2x + (-6) = 0

2x = +6

x = +3

Therefore, the oxidation state of one Carbon atom in the substance

The oxidation number of each carbon atom in

#### Explanation:

The sum of the oxidation numbers of the elements in a compound is zero.

The oxidation number for sodium is pretty much always

Since there are two sodium atoms, the

totaloxidation number for sodium is#+2# .

The oxidation number for oxygen is

Since there are four oxygen atoms, the

totaloxidation number for the oxygen atoms is#-8# .The sum of the oxidation numbers for sodium and oxygen is

#+2 - 8 = -6# . Therefore, thetotaloxidation number for carbon must be#+6# in order for the sum of the oxidation numbers to equal zero.Divide

#+6# by two to get the oxidation number of each carbon atom, which is#bb(+3)# .

Oxidation numbers for all elements in the compound sodium oxalate:

#stackrel(2 xx +1)("Na"_2)" "stackrel(2 xx +3)("C"_2)" "stackrel(4 xx -2)("O"_4)#

#2xx(+1)+2 xx (+3)+4xx(-2) = 0#