# What is the oxidation number of Cr in Cr2(SO4)3?

##### 1 Answer

Should be

#### Explanation:

With finding oxidation numbers, you have to know the common oxidation states of an element. There might be some little algebra involved.

(1) Fast answer: the sulfate ion (**+3** .

(2) Long answer: Most often than not, the oxidation state of oxygen is **-2** (mainly due to it being a member of Group 6 in the periodic table and it being electronegative). Since sulfur and oxygen atoms are enclosed in a parenthesis, this means that they are in covalent bond with each other and are therefore "sharing" electrons. So if the oxygen is negatively charged, the sulfur must be positively charged.

Substituting the values of oxidation states in the formula,

*x* then

#2x + [(+6) * (3) + (-2) * (4) * (3)] = 0#

#2x + (+18) + (-24) = 0#

#2x + (-6) = 0#

#2x = +6 implies x = +3#

Therefore, correct answer is

**Addendum** The element chromium, can only have two oxidation states: