What is the oxidation number of Na?

Jun 9, 2018

Elemental sodium has an oxidation number of $0$...the same as for ANY element....

Explanation:

Oxidation number is conceived to be the charge associated with a given atom, when it donates or accepts electrons according to predetermined rules...given here for your chemical pleasure....

$\text{1. The oxidation number of a free element is always 0.}$

$\text{2. The oxidation number of a mono-atomic ion is equal}$ $\text{to the charge of the ion.}$

$\text{3. For a given bond, X-Y, the bond is split to give } {X}^{+}$ $\text{and}$ ${Y}^{-}$, $\text{where Y is more electronegative than X.}$

$\text{4. The oxidation number of H is +1, but it is -1 in when}$ $\text{combined with less electronegative elements.}$

$\text{5. The oxidation number of O in its}$ compounds $\text{is usually -2, but it is -1 in peroxides.}$

$\text{6. The oxidation number of a Group 1 element}$ $\text{in a compound is +1.}$

$\text{7. The oxidation number of a Group 2 element in}$ $\text{a compound is +2.}$

$\text{8. The oxidation number of a Group 17 element in a binary compound is -1.}$

$\text{9. The sum of the oxidation numbers of all of the atoms}$ $\text{in a neutral compound is 0.}$

$\text{10. The sum of the oxidation numbers in a polyatomic ion}$ $\text{is equal to the charge of the ion.}$

And thus for elemental sodium we gots $N a \left(0\right)$.. Sodium is a good reductant, and for most of its reaction chemistry we get $N {a}^{+} \equiv N a \left(I +\right)$... In the given scenario, the metal has NEITHER accepted nor donated its single valence electron...