What is the oxidation number of Na?

1 Answer
Jun 9, 2018

Answer:

Elemental sodium has an oxidation number of #0#...the same as for ANY element....

Explanation:

Oxidation number is conceived to be the charge associated with a given atom, when it donates or accepts electrons according to predetermined rules...given here for your chemical pleasure....

#"1. The oxidation number of a free element is always 0."#

#"2. The oxidation number of a mono-atomic ion is equal"# #"to the charge of the ion."#

#"3. For a given bond, X-Y, the bond is split to give "X^+# #"and"# #Y^-#, #"where Y is more electronegative than X."#

#"4. The oxidation number of H is +1, but it is -1 in when"# #"combined with less electronegative elements."#

#"5. The oxidation number of O in its"# compounds #"is usually -2, but it is -1 in peroxides."#

#"6. The oxidation number of a Group 1 element"# #"in a compound is +1."#

#"7. The oxidation number of a Group 2 element in"# #"a compound is +2."#

#"8. The oxidation number of a Group 17 element in a binary compound is -1."#

#"9. The sum of the oxidation numbers of all of the atoms"# #"in a neutral compound is 0."#

#"10. The sum of the oxidation numbers in a polyatomic ion"# #"is equal to the charge of the ion."#

And thus for elemental sodium we gots #Na(0)#.. Sodium is a good reductant, and for most of its reaction chemistry we get #Na^+ -=Na(I+)#... In the given scenario, the metal has NEITHER accepted nor donated its single valence electron...