What is the oxidation number of Sn in the compound Na_2SnO_2?

1 Answer
May 29, 2016

+2

Explanation:

To find the oxidation number of Sn in Na_2SnO_2 we should know that:

The oxidation number for Na is always +1.

The oxidation number of O is always -2 except in H_2O_2 it is -1 and in OF_2 it is +2.

Let the oxidation number of Sn be x, therefore,

2xx(+1)+x+2xx(-2)=0

=>2+x-4=0

=>x-2=0

=>x=+2

Thus, the oxidation number of Sn in Na_2SnO_2 is +2.