What is the oxidation state of an individual sulfur atom in BaSO_4?

Jun 17, 2016

$S \left(V I +\right)$

Explanation:

The oxidation state of sulfur in $S {O}_{4}^{2 -}$ is calculated by taking the charge of the ion, $- 2$, and subtracting the oxidation number of oxygen, which is typically $- I I$.

Thus $- 2 = {S}_{\text{ON}} - 4 \times \left(- 2\right)$ $=$ ??