# What is the oxidation state of each element in Mn(CrO_4)?

##### 1 Answer
Jun 14, 2016

$M n \left(I I +\right) , C r \left(V I +\right) , O \left(- I I\right)$.

#### Explanation:

The typical oxidation state of oxygen is $- I I$, and it is here. Manganese typically takes a $+ I I$ oxidation state. This leaves chromium to balance the oxidation states (the oxidation states must sum to zero in a neutral compound). Thus $2 - 8 + C {r}_{\text{oxidation state}} = O$.

We have $C r \left(V I +\right)$, which is its maximum oxidation number