Question

What is the percent of increase from 270cm³ to 750cm³?

Answer 1

`177.77bar7%` not accurate solution.

`177 7/9 %` accurate solution.

Explanation:

Method`-> ("difference")/("original value")xx100`

`=> (750-270)/270xx100 = 177.77bar7%`

The bar over the last 7 means it goes on repeating for ever.
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
There is a trick you can use to deal with repeating decimals
You convert them to fractions. Sometimes you need to multiply by a different value: `10^n` as appropriate

Let `x=177.77bar7`

The `10x=1777.77bar7`

So `10x-x ->1777.77bar7`
`" "ul(" "177.77bar7)" "larr" subtract"`
`" "1600`

So `9x=1600 => x= 1600/9 = 177 7/9 %`