Question

What is the perimeter of a triangle with corners at `(1 ,4 )`, `(6 ,7 )`, and `(4 ,5 )`?

Answer 1

Perimeter is `(5.831+2.828+3.162)=11.821`

Explanation:

Let us find the distance between each pair of points A`(1,4)`, B`(6,7)` and C`(4,5)`.

AB=`c`=`sqrt((6-1)^2+(7-4)^2)=sqrt(25+9)=sqrt34=5.831`

BC=`a`=`sqrt((6-4)^2+(7-5)^2)=sqrt(4+4)=sqrt8=2.828`

AC=`b`=`sqrt((4-1)^2+(5-4)^2)=sqrt(9+1)=sqrt10=3.162`

Hence perimeter is `(5.831+2.828+3.162)=11.821`