# What is the perimeter of a triangle with corners at (6 ,4 ), (8 ,2 ), and (5 ,7 )?

##### 1 Answer
Mar 22, 2017

Perimeter of Triangle = $11.8216566798$ units
(or) √(8) + √(34) + √(10)

#### Explanation:

Vertices of Triangle are $\left(6 , 4\right) , \left(8 , 2\right) , \mathmr{and} \left(5 , 7\right)$
Distance $= \sqrt{{\left(x 2 - x 1\right)}^{2} + {\left(y 2 - y 1\right)}^{2}}$

Using Distance Formula

Find distance between (6,4),(8,2) and (8,2),(5,7) and (5,7),(6,4)

Then we get,
Distance between (6,4),(8,2) = $\sqrt{8}$

Distance between (8,2),(5,7) = $\sqrt{34}$

Distance between (5,7),(6,4) = $\sqrt{10}$

Add them we get Perimeter of the Triangle

√(8) + √(34) + √(10) = 11.8216566798 units