# What is the perimeter of a triangle with corners at (7 ,5 ), (1 ,6 ), and (4 ,3 )?

Jan 8, 2018

Perimeter of the triangle $P = \ast 13.931 \ast$

#### Explanation:

First to find the three sides a, b, c.

$a = \sqrt{{\left(6 - 5\right)}^{2} + {\left(1 - 7\right)}^{2}} = 6.0828$

$b = \sqrt{{\left(4 - 1\right)}^{2} + {\left(3 - 6\right)}^{2}} = 4.2426$

$c = \sqrt{{\left(7 - 4\right)}^{2} + {\left(5 - 3\right)}^{2}} = 3.6056$

Perimeter of the triangle $P = \frac{a + b + c}{2}$

$P = \frac{6.0828 + 4.2426 + 3.6056}{2} = 13.931$