# What is the pH of 10^(-2) "M HCl" solution?

Apr 6, 2018

$2$

#### Explanation:

Because

["H"^(+)]= 10^-"pH"

Therefore, the exponent of $10$ is the pH and this makes sense because the $\text{pH}$ $\left(2\right)$ is less than $7$, which indicates that it should be an acid. This is true because $\text{HCl}$ is a strong acid, i.e.

$\left[\text{H"^(+)] = ["HCl}\right]$

Apr 6, 2018

$2$

#### Explanation:

Hydrochloric acid is a strong acid which dissociates into single hydrogen $\left({H}^{+}\right)$ ions in an aqueous solution.

The $\text{pH}$ of a solution is given by the equation,

$\text{pH} = - \log \left[{H}^{+}\right]$

• $\left[{H}^{+}\right]$ is the hydrogen ion concentration in terms of molarity

And so, we got:

$\text{pH} = - \log \left[{10}^{-} 2\right]$

$= 2$