What is the pH of a 0.35 M #NH_4Cl# solution?

1 Answer
Jun 11, 2016

Answer:

And what is #pK_a# for #"ammonium chloride"#?

Explanation:

For the reaction:

#NH_4^+ + H_2O(l) rightleftharpoons NH_3(aq) + H_3O^+#

#K_a# #=# #([NH_3(aq)][H_3O^+])/([NH_4^+])#

#K_a# #=# #x^2/(0.35-x)#, where #x# #=# #[H_3O^+]# #=# #[NH_3]#

#pH# #=# #-log_10[H_3O^+]# may be solved exactly, once we have details of #K_a#. And #K_a# #=# #???#