What is the pH of a 0.35 M NH_4Cl solution?

Jun 11, 2016

And what is $p {K}_{a}$ for $\text{ammonium chloride}$?

Explanation:

For the reaction:

$N {H}_{4}^{+} + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s N {H}_{3} \left(a q\right) + {H}_{3} {O}^{+}$

${K}_{a}$ $=$ $\frac{\left[N {H}_{3} \left(a q\right)\right] \left[{H}_{3} {O}^{+}\right]}{\left[N {H}_{4}^{+}\right]}$

${K}_{a}$ $=$ ${x}^{2} / \left(0.35 - x\right)$, where $x$ $=$ $\left[{H}_{3} {O}^{+}\right]$ $=$ $\left[N {H}_{3}\right]$

$p H$ $=$ $- {\log}_{10} \left[{H}_{3} {O}^{+}\right]$ may be solved exactly, once we have details of ${K}_{a}$. And ${K}_{a}$ $=$ ???