Question

What is the pH of a 4.8 x 10^-10 M H+ Solution?

Answer 1

pH = 9,32

Explanation:

you have two relations:
pH + pOH = 14
`[H^+] xx [OH^-] = 10^(-14)`
and two definitions:
`pH = -Log[H^+]` and
`pOH = -Log[OH^-]`
if you you know use logarithms, with these you can solve all the problems you asked about pH.
in this case
`pH = log (4.8 xx 10^-10) =9.32`
pOH = 14-pOH = 4,68