# What is the pH of a .500 M solution of HNO_3?

$p H = 0.30$
$H N {O}_{3} \left(a q\right) + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s {H}_{3} {O}^{+} + N {O}_{3}^{-}$
$p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$. Since the equilibrium lies almost entirely to the right, we take $\left[{H}_{3} {O}^{+}\right] = 0.500 \cdot m o l \cdot {L}^{-} 1$.
${\log}_{10} \left(0.500\right)$ $=$ $- 0.301$, and pH=??