Question

What is the pOH of 2.15 M `Ba(OH)_2` solution? Is the solution neutral, acidic, or basic?

Answer 1

`pOH` `=` `-log_(10)[HO^-]` `=` `??`

Explanation:

Given `2.15*mol*L^-1` barium hydroxide, `[HO^-]` `=` `4.30*mol*L^-1`

`pOH` `=` `-log_(10)[HO^-]` `=` `-log_(10){4.30}` `=` `-0.63`.

The solution is strongly basic.