# What is the pOH of 2.15 M Ba(OH)_2 solution? Is the solution neutral, acidic, or basic?

$p O H$ $=$ $- {\log}_{10} \left[H {O}^{-}\right]$ $=$ ??
Given $2.15 \cdot m o l \cdot {L}^{-} 1$ barium hydroxide, $\left[H {O}^{-}\right]$ $=$ $4.30 \cdot m o l \cdot {L}^{-} 1$
$p O H$ $=$ $- {\log}_{10} \left[H {O}^{-}\right]$ $=$ $- {\log}_{10} \left\{4.30\right\}$ $=$ $- 0.63$.