# What is the pOH of a 6.5*10^-12 M OH^- solution?

Jul 2, 2016

$p O H \cong 11.$
$p O H = - {\log}_{10} \left[H {O}^{-}\right]$
$- {\log}_{10} \left\{6.5 \times {10}^{-} 12\right\}$ $=$ $11.2$
What is the $p H$ of this solution? You should not need a calculator.