# What is the point-slope form of an equation with the slope 3⁄5 that passes through the point (10, −2)?

Answer: $y + 2 = \frac{2}{5} \left(x - 10\right)$
$y - {y}_{0} = m \left(x - {x}_{0}\right)$
where $m$ is the gradient and $\left({x}_{0} , {y}_{0}\right)$ is the point through which the line passes
so you do $y - \left(- 2\right) = \frac{3}{5} \left(x - 10\right)$
$\implies y + 2 = \frac{3}{5} \left(x - 10\right)$