What is the point-slope of the equation of the line passing through (-1,4) parallel to #y=-5x+2#?

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Answer 1 · 2015-06-23T19:37:15

The point-slope form of the equation of the required line is:

#y - 4 = -5(x - (-1))#

The equation #y = -5x + 2# is in slope-intercept form, describing a line of slope #-5# with intercept #2#.

Any line parallel to it will have slope #-5#.

Point slope form is:

#y - y_1 = m(x - x_1)#

where #m# is the slope and #(x_1, y_1)# is a point on the line.

So with slope #m=-5# and #(x_1, y_1) = (-1, 4)#, we get:

#y - 4 = -5(x - (-1))#

The same line in slope-intercept form is:

#y = -5x + (-1)#