What is the polar form of #(1,18)#?

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Answer 1 · 2016-06-01T20:36:43

#(r,theta)=(5sqrt(13),arctan(18))#

Given Cartesian coordinates #(x,y)# in Quadrant I

#r=sqrt(x^2+y^2)#
and
#theta=arctan(y/x)#

Answer 2 · 2016-06-01T20:49:20

(18, 1.5)

Polar format: (r, #theta#)

#r=sqrt(x^2+y^2)#

#theta = tan^-1(y/x)#

apply both formulas when going from Cartesian -> polar

#sqrt(1^2+18^2) = sqrt(325) ~~ 18.0#

#theta = tan^-1(18/1) = tan^-1(18) ~~ 1.5 radians#

Thus our answer of:

Polar format of (1,18) Cartesian is:

(18, 1.5)