# What is the polar form of (1,2)?

$\left(\sqrt{5} , {1.11}^{c}\right)$
For given $\left(x , y\right)$ coordinates, $\left(x , y\right) \to \left(r , \theta\right)$ where $r = \sqrt{{x}^{2} + {y}^{2}}$ and $\theta = {\tan}^{-} 1 \left(\frac{y}{x}\right)$
$\left(1 , 2\right) \to \left(r , \theta\right) = \left(\sqrt{{1}^{2} + {2}^{2}} , {\tan}^{-} 1 \left(2\right)\right) \approx \left(\sqrt{5} , {1.11}^{c}\right)$