What is the polar form of #( 11,-99 )#?

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Answer 1 · 2018-06-01T22:11:41

Polar:
Exact: #(11sqrt(82), tan^-1(-9))#
About: #(99.61, -1.46)

Cartesian form: #(x,y)#

Polar form: #(r, theta)#

#r = sqrt(x^2+y^2)#

#r = sqrt(11^2+99^2) = 11sqrt(82)~~99.61#

#theta = tan^-1(y/x)#

#theta = tan^-1(-99/11)#

#theta = tan^-1(-9) ~~ -1.46#

Exact