# What is the polar form of ( 16,0 )?

Dec 6, 2015

rectangular form: $\left(x , y\right) = \left(16 , 0\right)$
polar form: $\left(r , \theta\right) = \left(16 , 0\right)$

#### Explanation:

$\left(16 , 0\right)$ in rectangular form is a point $16$ units away from (and to the right of) the origin.
So the radius is $r = 16$.

$\left(16 , 0\right)$ lies on the X-axis (so the angle between the line connecting it to the origin and the X-axis is 0).
So the angle $\theta = 0$.